If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2m^2+5m-18=0
a = 2; b = 5; c = -18;
Δ = b2-4ac
Δ = 52-4·2·(-18)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-13}{2*2}=\frac{-18}{4} =-4+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+13}{2*2}=\frac{8}{4} =2 $
| 3t-12+5t+3t+5=180 | | 2m2+5m-18=0 | | 2x-4/4-(1-x)/6=17 | | 4y+10+2y+5y-14=180 | | 2^x+3=1/32 | | 3x+9=4x-2+3x | | 5(2x-1)=5(5-14) | | 32=3z-2 | | 8x4=X(x•7)-(x•3) | | 5x−3−7x=15−x | | 7y-4=3 | | -2(5x-7)=34 | | 5(2x-1)=(5x-14) | | 40+x=369 | | 2(7r-9)=24 | | 5w−13=32 | | f/5−20=−29 | | -3(2x-6)+5(3x-4)=25 | | -3(2x+5)+5(3x+6)=42 | | 7+s=3 | | 4(3x+5)-3(2x+4)=20 | | k/18=12.1/3 | | 4(2x+4)+5(3x-6)=-83 | | 3(3x+6)+2(2x+5)=67 | | 4x=40000 | | -5(4x+6)+3x-7=14 | | 3(5x-6)-4x+8=23 | | x-(x*0.16)=0 | | 6(2x+5)+4x+6=84 | | -6(3x+6)=-114 | | k/18=37/3 | | x-0.16x=0 |